If velocity doubles, the dynamic pressure term (1/2)p v^2 increases by a factor of:

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Multiple Choice

If velocity doubles, the dynamic pressure term (1/2)p v^2 increases by a factor of:

Explanation:
Dynamic pressure scales with the square of velocity. It’s defined as q = 1/2 ρ v^2, where ρ is air density. If velocity doubles, v becomes 2v, and (2v)^2 = 4v^2, so q becomes four times larger (assuming density remains the same). That’s why the correct result is a fourfold increase. The other options would imply a linear change or a different relationship, which doesn’t match the v^2 dependence.

Dynamic pressure scales with the square of velocity. It’s defined as q = 1/2 ρ v^2, where ρ is air density. If velocity doubles, v becomes 2v, and (2v)^2 = 4v^2, so q becomes four times larger (assuming density remains the same). That’s why the correct result is a fourfold increase. The other options would imply a linear change or a different relationship, which doesn’t match the v^2 dependence.

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